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r^2+r=24/25
We move all terms to the left:
r^2+r-(24/25)=0
We add all the numbers together, and all the variables
r^2+r-(+24/25)=0
We get rid of parentheses
r^2+r-24/25=0
We multiply all the terms by the denominator
r^2*25+r*25-24=0
Wy multiply elements
25r^2+25r-24=0
a = 25; b = 25; c = -24;
Δ = b2-4ac
Δ = 252-4·25·(-24)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-55}{2*25}=\frac{-80}{50} =-1+3/5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+55}{2*25}=\frac{30}{50} =3/5 $
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